Monday, 13 June 2016

PLSQL PROGRAMS TO PRACTICE 4

52.WAP to accept the basic salary and find out the ta,da,hra,lic and gs
i)ta 20% of basic, da 10% of basic, hra 30% of basic, lic 5% of basic

DECLARE
BS NUMBER(6,2):=&BS;
TA NUMBER(6,2);
DA NUMBER(6,2);
HRA NUMBER(6,2);
GS NUMBER(6,2);
LIC NUMBER(6,2);
NS NUMBER(8,2);
BEGIN
TA:=BS*(20/100);
HRA:=BS*(30/100);
DA:=BS*(10/100);
LIC:=BS*(5/100);
GS:=TA+HRA+DA;
NS:=GS-LIC;
DBMS_OUTPUT.PUT_LINE('EMPLOYEE BS IS '||BS);
DBMS_OUTPUT.PUT_LINE('GROSS SALARY IS '||GS);
DBMS_OUTPUT.PUT_LINE('NET SALARY IS '||NS);
END;
/

53.WAP to accept the length and breadth of a rectangle and find out the perimeter

DECLARE
L NUMBER(4,2):=&L;
B NUMBER(4,2):=&B;
A NUMBER(4,2);
BEGIN
A:=2*(L+B);
DBMS_OUTPUT.PUT_LINE('THE PERIMETER OF RECTANGLE IS '||A);
END;
/

54.WAP to accept the cost price and selling price of an item and find
the loss or profit

DECLARE
CP NUMBER(25,2):=&CP;
SP NUMBER(25,2):=&SP;
AMT NUMBER(7,2);
BEGIN
IF CP < SP THEN
AMT:=SP-CP;
DBMS_OUTPUT.PUT_LINE('PROFIT IS '||AMT);
ELSE
AMT:=CP-SP;
DBMS_OUTPUT.PUT_LINE('LOSS IS '||AMT);
END IF;
END;
/

55.Writ a program to generate the following series
53 53 53 53 53
43 43 43 43
33 33 33
23 23
13

DECLARE
V VARCHAR2(20);
BEGIN
FOR I IN REVERSE 1..5
LOOP
FOR J IN 1..I
LOOP
V:=V||I||CHR(179);
END LOOP;
DBMS_OUTPUT.PUT_LINE(V);
V:=NULL;
END LOOP;
END;
/

56.WAP to accept a no in binary format and print it in decimal format

DECLARE
N VARCHAR2(20):=&N;
PRO NUMBER(10,4):=0;
L VARCHAR2(10);
BEGIN
FOR I IN 1..LENGTH(N)
LOOP
L:=SUBSTR(N,I,1);
PRO:=PRO+L*POWER(2,LENGTH(N)-I);
END LOOP;
DBMS_OUTPUT.PUT_LINE('THE DECIMAL NUMBER IS '||PRO);
END;
/

57.WAP to accept two nos and input and find one no is raised to another one (without using any function)

DECLARE
A NUMBER:=&A;
B NUMBER:=&B;
R NUMBER:=1;
BEGIN
FOR I IN 1..B
LOOP
R:=R*A;
END LOOP;
DBMS_OUTPUT.PUT_LINE('A RAISED POWER B IS '||R);
END;
/

58.WAP to accept a sentence and count the no of chars in that sentence

DECLARE
STR VARCHAR2(100):='&STR';
NO NUMBER(5):=0;
I NUMBER;
BEGIN
I:=INSTR(STR,'.');
DBMS_OUTPUT.PUT_LINE('NO OF CHAR IS '||I);
END;
/

59.WAP to accept two strings and display the large one among those

DECLARE
STR1 VARCHAR2(100):='&STR1';
STR2 VARCHAR2(100):='&STR2';
BEGIN
IF LENGTH(STR1) > LENGTH(STR2) THEN
DBMS_OUTPUT.PUT_LINE(STR1 ||' IS GREATER');
ELSIF LENGTH(STR1) < LENGTH(STR2) THEN
DBMS_OUTPUT.PUT_LINE(STR2 ||' IS GREATER');
ELSE
DBMS_OUTPUT.PUT_LINE('BOTH STRINGS ARE EQUAL');
END IF;
END;
/

60.WAP to display all the nos whose sum of digits is 9 from 1 to 9999

DECLARE
N NUMBER;
M NUMBER;
S NUMBER:=0;
BEGIN
FOR I IN 1..999
LOOP
N:=I;
WHILE N>0
LOOP
M:=MOD(N,10);
S:=S+M;
N:=TRUNC(N/10);
END LOOP;
IF S=9 THEN
DBMS_OUTPUT.PUT_LINE(I||' ');
END IF;
S:=0;
END LOOP;
END;
/

61.WAP to accept a no and find the sum in a single digit

DECLARE
N NUMBER(4):=&N;
S NUMBER(10):=0;
BEGIN
WHILE LENGTH(N)>1
LOOP
FOR I IN 1..LENGTH(N)
LOOP
S:=S+SUBSTR(N,I,1);
END LOOP;
N:=S;
S:=0;
END LOOP;
DBMS_OUTPUT.PUT_LINE('THE SUM IN SINGLE DIGIT IS '||N);
END;
/

62.Ente the no of days and find out the no of years and no of days and months

DECLARE
D NUMBER:=&D;
Y NUMBER;
M NUMBER;
BEGIN
Y:=TRUNC(D/365);
M:=TRUNC(MOD(D,365)/30);
D:=MOD(MOD(D,365),30);
DBMS_OUTPUT.PUT_LINE(Y||' YEARS '||M||' MONTHS '||D||' DAYS');
END;
/

63.WAP to accept the date and print all the weekdays along with the given date

DECLARE
D DATE:='&D';
V VARCHAR2(20);
BEGIN
FOR I IN 1..7
LOOP
V:=TO_CHAR(D,'DAY')||D;
DBMS_OUTPUT.PUT_LINE(V);
D:=D+1;
END LOOP;
END;
/

64.WAP while purchasing certain items,discount of each is as follows
i) If qty purchased > 1000 discount is 20%
ii) If the qty and price per item are i/p then calculate the expenditure

DECLARE
QTY NUMBER(5):=&QTY;
UP NUMBER(6,2):=&UP;
DIS NUMBER(6,2):=0;
TAMT NUMBER(10,2);
BILL NUMBER(10,2);
BEGIN
BILL:=QTY*UP;
IF BILL > 1000 THEN
DIS:=BILL*20/1000;
END IF;
TAMT:=BILL-DIS;
DBMS_OUTPUT.PUT_LINE('THE TOTAL AMOUNT IS '||TAMT);
END;
/

65.Write a program to accept a string and count the no of individual chars

DECLARE
V VARCHAR2(100):='&V';
V1 VARCHAR2(100);
LB NUMBER;
LA NUMBER;
DIFF NUMBER;
C CHAR;
N NUMBER(5):=0;
BEGIN
V1:=V;
WHILE LENGTH(V1)>0
LOOP
C:=SUBSTR(V1,1,1);
LB:=LENGTH(V1);
V1:=REPLACE(V1,C);
LA:=NVL(LENGTH(V1),0);
DIFF:=LB-LA;
IF ASCII(C)=32 THEN
DBMS_OUTPUT.PUT_LINE('SPACE'||' EXISTS '||DIFF||' TIMES');
ELSE
DBMS_OUTPUT.PUT_LINE(C||' EXISTS '||DIFF||' TIMES');
END IF;
N:=N+DIFF;
END LOOP;
DBMS_OUTPUT.PUT_LINE('TOTAL LENGTH OF THE GIVEN STRING '||V||'='||N);
END;
/

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